Calculate the maximum numbers of moles and grams of iodic acid (HIO3) that can form when 547 g of iodine trichloride reacts with 224.5 g of water: ICl3 + H2O → ICl + HIO3 + HCl [unbalanced]
___mol HIO3
___g HIO3
What mass of the excess reactant remains?____g
Calculate the maximum numbers of moles and grams of iodic acid (HIO3) that can form when...
Calculate the maximum numbers of moles and grams of iodic acid (HIO3) that can form when 679g of iodine trichloride reacts with 115.6 g of water: _________ mol _________ g ICI3 + H2O ---> ICl + HIO3+ HCl [unbalanced] What mass of the excess reactant remains? What is that reactant? __ ICl3 __ H2O
Calculate the maximum numbers of moles and grams of iodic acid (HlO3) that can form when 338 g of iodine trichloride reacts with 159.7 g of water: ICl3 + H2O → ICl + HIO3 + HCl (unbalanced) _____ mol HlO3 _____ g HlO3 What mass of the excess reactant remains? _____ g
Calculate the maximum numbers of moles and grams of iodic acid (HIO3) that can form when 431 g of iodine trichloride reacts with 214.2 g of water: ICly+ Ho ICI+HIO+HCI (unbalanced mol HIO3 HIO What mass of the excess reactant remains?
Question 1: Be sure to answer all parts. Calculate the maximum numbers of moles and grams of iodic acid (HIO3) that can form when 622 g of iodine trichloride reacts with 124.1 g of water: ICl3 + H2O → ICl + HIO3 + HCl [unbalanced] mol HIO3? g HIO3? What mass of the excess reactant remains in grams? Question 2: Be sure to answer all parts. When 0.107 mol of carbon is burned in a closed vessel with 5.06 g...
Calculate the maximum numbers of moles and grams of H2S that can form when 153.0 g of aluminum sulfide reacts with 143.0 g of water: Al2S3 + H2O → Al(OH)3 + H2S [unbalanced] ______ mol H2S ______ g H2S What mass of the excess reactant remains? ______ g excess reactant
Make UP lef Check my work Be sure to answer all parts. Calculate the maximum numbers of moles and grams of H2S that can form when 127.3 g of sulfide reacts with 143.0 g of water: Al2Sg + H2O ? Al(OH)3 + H2S [unbalanced] mol H2S g H2S What mass of the excess reactant remains? g excess reactant
2 attempts left Check my work Be sure to answer all parts. Calculate the maximum numbers of moles and grams of HS that can form when 167.3 g of aluminum sulfide reacts with 143.0 g of water: Al,S3 + H,0 - Al(OH)3 + H2S (unbalanced) 3.34 14,5 133.9 XL, What mass of the excess reactant remains? 41.31 Xxcess reactant
Iodine reacts with chlorine to form iodine monochloride according to the following unbalanced reaction: I2 (s) + Cl2 (g) → ICl(g) If we start with 25.4 g of iodine and 37.4 g of chlorine, how many grams of the excess reactant are leftover after the reaction is complete? Answer in 3 significant figures:
Worksheet for quiz 2 (chapters 2 and 3) 1. (3 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g of water: ALS; + H2O + Al(OH)3 + H2S (unbalanced] How many grams of the excess reactant remain?
How many grams of NO and of H2O form? Enter your answers numerically separated by a comma. How many grams of the excess reactant remain after the limiting reactant is completely consumed? One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) In a certain experiment, 1.50 g of NH3 reacts with 2.75 g of O2.