(1) correct: Inceasing the volume of vessel will leads to form more Cl2 because the volume of product is more than reactant and hence to counter the effect of volume increase , the reaction should shift right hand side to fill more volume.
(2)False : Removing Cl2 will form more PCl3
(3)correct:decreasing volume will form more PCl5
(4)correct: Increasing pressure of PCl5 will form more PCl3
(5)False: Kc only depends on temperature and not on concentration
LeChatelier's Principle: Qualitative Interpretation Consider the following equilibrium: PCl5 (g)PCl3 (g) + Cl2 (9) Select all...
Consider the following system at equilibrium at 500 K: PCl5 (g) + 21.0 kcal PCl3 (g) + Cl2 (g) Indicate whether each individual change would favor the production of PCl3 (g). Evaluate each change separately, assuming that all other conditions remain constant. Decreasing the temperature. Decreasing the pressure. Increasing the volume. Removing PCl5 . Adding Cl2 . Yes or No answers please
The dissociation of PCl5(g) to PCl3(g) and Cl2(g) is an endothermic reaction. PCl5(g) PCl3(g) + Cl2(g) What is the effect on the position of equilibrium of each of the following changes? a) Compressing the gaseous mixture _________________________________ b) Decreasing the temperature _________________________________ c) Adding Cl2(g) to the equilibrium mixture __________________________________ d) Removing PCl5 (g) from the equilibrium mixture __________________________________
The equilibrium constant Kc for the reaction: PCl3(g) + Cl2(g) PCl5(g) is 490 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol of Cl2 in a 1.00-L reaction vessel at 230°C, what is the concentration of PCl3 when equilibrium has been established? (show work)
Consider the reaction. PCl5(g)−⇀↽−PCl3(g)+Cl2(g)Kc=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.180 M and [Cl2]=0.280 M. What is the concentration of the reactant, PCl5, at equilibrium?
Consider the reaction: PCl5 (g) ⇔ PCl3 (g) + Cl2 (g) The initial concentration of PCl5 is 0.40 M and the equilibrium concentration of PCl3 is 0.33 M. Calculate the equilibrium constant Kc.
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) -----> PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.504 moles of PCl3 and 0.504 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = _____ M [Cl2] = _____M [PCl5] = _____M
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.366 moles of PCl3 and 0.366 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = ____M [Cl2] = _____M [PCl5] = ____M
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) ⇌ PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.253 moles of PCl3 and 0.253 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = ___ M [Cl2] = ___ M [PCl5] = ___M
Phosphorus pentachloride decomposes according to the chemical equation PCl5(g) <=> PCl3 (g) + Cl2 (g) Kc = 1.80 at 250 C A 0.3391 mol sample of PCl5 (g) is injected into an empty 3.60 L reaction vessel held at 250 ∘ C. Calculate the concentrations of PCl5 ( g ) and PCl3 ( g ) at equilibrium. [PCl5] = __________M. [PCl3]=___________M.
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) = PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.249 moles of PCl3 and 0.249 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = M [Cl2] = M [PCl5] = M The equilibrium constant, Kc, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) = H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and...