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Use the given information to find the number of degrees of freedom, the critical values and χ,, and the confidence interval estimate of σ. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution Platelet Counts of Women 90% confidence; n = 23, s = 65.6. Click the icon to view the table of Chi-Square critical values df= □ (Type a whole number.) 尤- (Round to three decimal places as needed.) XR (Round to three decimal places as needed.) The confidence interval estimate of σ is「…く (Round to one decimal place as needed.) Enter your answer in each of the answer boxes.

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Answer #1

a) The degrees of freedom here are computed as:

df = n-1 = 22

b) Now for 90% confidence level and 22 degrees of freedom, we get from the chi square tables that:

P( \chi^2_{22}< 33.92) = 0.95

P( \chi^2_{22}<12.34) = 0.05

Therefore the critical values here are given as:

\chi^2_L = 33.920

\chi^2_R = 12.340

Now the confidence interval for the standard deviation here is computed as:

65.6*\sqrt{\frac{22}{33.92}} < \sigma < 65.6*\sqrt{\frac{22}{12.34}}

52.8 < \sigma < 87.6

Thisis the required confidence interval here.

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