Solution:
1 ) Shaded area = P(Z < 1.13 ) = 0.8708 ...use z table
2) Shaded area = P(Z > -1.82)
= 1 - P(Z < -1.82)
= 1- 0.0344
= 0.9656
3) Shaded area is 0.4013
Area is to the left of z score
P(Z < z score ) = 0.4013
From z table , search 0.4013 probability and see corresponding z value.
Required z score = -0.25
Find the area of the shaded region. The graph depicts the standard normal distribution with mean...
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