Question

1. HNO3 (aq) + CaCl2 (aq) -----> ?

2. Na2CO3 (aq) + KI (aq) -----> ?

please write out full ionic, net ionic, and type of reaction. Thank you!

Answer 1

1. The molecular equation is given as

2 HNO3 (aq) + CaCl2 (aq) ----------> Ca(NO3)2 (aq) + 2 HCl (aq)

Both the reactants are ionic compounds and hence, decompose completely in aqueous solutions. Decompose the ionic species into ions and write

2 H+ (aq) + 2 NO3- (aq) + Ca2+ (aq) + 2 Cl- (aq) ----------> Ca2+ (aq) + 2 Cl- (aq) + 2 H+ (aq) + 2 Cl- (aq)

Cancel the common ions from both sides to get the net ionic equation. However, since, both the products are ionic compounds, hence, all the ions cancel out. Therefore, the net ionic equation appears as though no reaction occurs.

Since the anions simply change their positions, hence, the reaction is a double displacement reaction.

2. The molecular equation is given as

Na2CO3 (aq) + 2 KI (aq) ---------> 2 NaI (aq) + K2CO3 (aq)

Both the reactants are ionic compounds and hence, decompose completely in aqueous solutions. Decompose the ionic species into ions and write

2 Na+ (aq) + CO32- (aq) + 2 K+ (aq) + 2 I- (aq) ----------> 2 Na+ (aq) + 2 I- (aq) + 2 K+ (aq) + CO32- (aq)

Cancel the common ions from both sides to get the net ionic equation. However, since, both the products are ionic compounds, hence, all the ions cancel out. Therefore, the net ionic equation appears as though no reaction occurs.

Since the anions simply change their positions, hence, the reaction is a double displacement reaction.