Let ,
Therefore , The PMF of X is ,
; x=0,1,2,...........,n and q=1-p
= 0 ; otherwise
The probability distribution table is ,
X | ||||
0 | 1 | 1 | 0.0404 | 0.0404 |
1 | 9 | 0.3 | 0.0576 | 0.1556 |
2 | 36 | 0.09 | 0.0824 | 0.2668 |
3 | 84 | 0.027 | 0.1176 | 0.2668 |
4 | 126 | 0.0081 | 0.1681 | 0.1715 |
5 | 126 | 0.0024 | 0.2401 | 0.0735 |
6 | 84 | 0.0007 | 0.343 | 0.021 |
7 | 36 | 0.0002 | 0.49 | 0.0039 |
8 | 9 | 7E-05 | 0.7 | 0.0004 |
9 | 1 | 2E-05 | 1 | 2E-05 |
1)
2)
3)
4)
5) P(X=0)= 0.0404
6) P(X=7)=0.0039
7)
8)
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