Question

For the first part I got 1 and 0 chiral centers, but do not know how...

For the first part I got 1 and 0 chiral centers, but do not know how to find stereo centers.
I also do not understand how parts of one molecule can be constitutional isomers or same compounds, but not the whole molecule.

Please answer!

For the first part I got 1 and 0 chiral centers, b
0 0
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Answer #1

Solution :-

Q1) The structure in which the C=C are rpesent can considered as stereocenters also the chiral centers are also considred as stereocenters but not all stereocenters are chiral centers

Threfore in the first structure 4 chiral centeres are present which are also considred as stereomeceters therefore it has 4 chiral and 4 stereocenters

in the second structure 2 chiral centeres are present which are also considred as stereomeceters therefore it has 2 chiral and 2 stereocenters

Q2) To assign the configurations of the chiral carbons we provide the priority numbers to the groups attached to the chiral center based on the atomic numbers and then determine the direaction of arrow moving through the priority numbers originating from 1 and goin to 3. considering the 4th priority group is below the plane then if the direction is clockwise then its R configuration and if the direction is counter clockwise then its S configuration if the 4th priority number is not below the plane then the configuration is inverted.

Given structures differ in the configuration of the chiral centers and they are also not the mirror images of each other therefore they are diastereomers.

Q3) The carbocations which are in conjugation with the double bonds can rearrange by the resonance effect. The structure which can resonate are shown in the green boxes

No. Stereocenters: No. Stereocenters: No. Chiral centers: 4 chiralor achiral No. Chiral centers: Chiral or achiral 2. il up t

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