Question

1. Chickens having a mass of 5 kg are immersion frozen in propylene glycol at -30°C (ρ=1068 kg/m3). If the volume of each vacuum packaged bird is about 6000 cm3, what force must be applied to each bird to keep it at mid-depth in the 1-m deep tank?

Answer 1

evitational F = Applied force. ng for gravity (Gravitational force) Fy= buoyant force, 299 vi Now, sgv = Ft mga g' = density of propylene glycol = 1068 kg/m3 g= arch due to gravity = 8.3 m5², va volume displaced = volume of chicken. 2, 6000 cm3 . -0.006 m3 ma mass of chicken = 5kg. F = 1068 x 9.8 0.00 6- 5 X 9.8 N - 62.8 - 49 Ni F = 13.8 No Force to be able toeach bird cindependent of depth) pplied