Homework Answers
CODE
def sameKeys(diction1, diction2):
if diction1 is None or diction2 is None:
return None
diction3 = {}
for key in diction1:
if key in diction2:
lst = []
lst.append(diction1[key])
lst.append(diction2[key])
diction3[key] = lst
return diction3
dict1 = {1: 'a', 2: 'b', 3: 'c', 4: 5}
dict2 = {1: 333, 3: 'k', 4: ['o', 'p']}
print(sameKeys(dict1, dict2))
![1 def sameKeys (dictionl, diction2): 2 if dictionl is None or diction2 is None: GCC 4.8.2] on Linux 1: Ca, 333], 3: Cc, k](http://img.homeworklib.com/questions/fd2a9d00-d419-11ea-8298-31e9e0d26995.png?x-oss-process=image/resize,w_560)
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