from above
a)
option A is correct
crtiical value = -1.699
test statistic tx = -2.47
p value =0.010
Conclusion: option C
b) please revert if only 2 options are available
also find p value. During the winter of 2008-2009, the average ulity bil for nesidents of...
During the winter of 2008-2009, the average utility bill for residents of a certain state was $184 per month. A random sample of 40 customers was selected during the winter of 2009-2010, and the average bill was found to be $174.91 with a sample standard deviation of $19.47 .Complete parts a and b below. a) Using alpha=0.05 ,does this sample provide enough evidence to conclude that the average utility bill in this state was lower in the winter of 2009-2010...
During the winter of? 2008-2009, the average utility bill for residents of a certain state was ?$184 per month. A random sample of 30 customers was selected during the winter of? 2009-2010, and the average bill was found to be ?$174.49 with a sample standard deviation of ?$19.66. Complete parts a and b below. ?a) Using alphaequals0.05?, does this sample provide enough evidence to conclude that the average utility bill in this state was lower in the winter of? 2009-2010...
According to research, holiday shoppers spent an average of $368 over a holiday weekend in 2008. The accompanying data show the amount spent by a random sample of holiday shoppers during the same weekend in 2009. Complete parts a and b below. EEB Click the icon to view the data table a. Retailers were concerned that the recent economic downturn was going to affect holiday sales Does this sample support these concems using α= 0.10? Determine the null and alternative...
Question # 1 answer a through c The second page is same question but couldn’t take one page so please answer a through c C. Use technology to determine the p-value for this test? P-value= During the winter or 2003-2009, the average utility bll for residents or a certain state was S 182 per month. A tandom sample of 60 c was selecled during the winter of 2009 2010, and the average ba was found to be $174?4 with a...
Can someone explain to me how to get the p-value using a TI-84 calculator? I’m so lost. Thanks! Homework: HW 8.3 Testing a claim about Population Mean Score: 0.83 of 1 pt 11 of 16 (16 complete) ▼ Hw Score: 98.07%, 15.69 of 16 pt & 8.3.15-T Question Help levels were measured before and after the In a test of the effe treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of...
b) Identify the P-value and state the researcher’s conclusion if the level of significance was a = 0.001. What is the P-value? P = __ State the researcher’s conclusion. Which of the following is correct? A. Fail to reject H0, there is not sufficient evidence to conclude that the mean step pulse of men was less than the mean step pulse of women. B. Reject H0, there is not sufficient evidence to conclude that the mean step pulse of men...
Find the p-value show work. STA 3123 U01- Spring 2019 omework: Section 8.5 Homework core: 0 of 1 pt Kath 70f9(9 complete) ▼ 8.5.57-T sample of five measurements, randomly selected from a normally distributed population, resulted in the folowing summary statistics: x 4.7, s1.2. Complete parts a. Test the null hypothesis that the mean of the population is 6 against the afternative hypothesis, u 6. Use -0.01 lf α. 0.01, find te rejection region for the test. Choose the correct...
People tend to be more generous after receiving good news. Are they less generous after receiving bad news? The average tip left by adult Americans is 21%. Give 20 patrons of a restaurant a message on their bill warning them that tomorrow's weather will be bad and record the percentage tip they leave. Given are the tips as a percentage of the total bil. 18 19.119.2 18.8 18.4 19 18.5 16.1 16.8 18.2 14 1713.6 17.5 20 20.2 18.818 23.2...
The average daily volume of a computer stock in 2011 was u = 35.1 milion shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 40 trading days in 2014, he finds the sample mean to be 25,3 million shares with a standard deviation of s 12.1 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through...
A genetic engineering average more tomatoes than other varieties. A farmer wants to test the claim on a small sca company claims that it has developed modified tomato plant that full-scale planting. Ten genetically modified tomato plants are grown from seeds along At the season's end, the resulting yields in pound are recorded as below Sample 1 Sample 2 Modified Regular o test the claim on a small scale before committing to a own from seeds along with ten other...