Question

2. Consider the circuit shown below. (8 points) What is the equivalent capacitance between points a and b? 1 uF RA LLLL AN INN LEE Il 2 UF 12 uf

Answer 1

The equivalent capacitance for the series connection is given by, ceq and for the parallel connection is given by, Ceq = CitCat Co tonn. EINF A=IFF 11B=INE CB=INE c=2pF Soapf b. G=BNF E=INF &=INF G=BNF In this figuse A and B capaurons doe in parallel combination. Simillasly codD capautons are in parallel combinahon. Hence the ciscaut can be simplify as VU CAB - CA+CB - INF+ INF= QUF Co- Cetco - 2NF+2 pF = 4Nf ? since they are in parallel connection. Now CAR and CE are in series connection. simillalily Cep and CF are in besies connection. Hence the Crescent simplified as

CAGE COF Con = Cave+ -+- 3M . .. CARE = 3/NF Coor = + 2 = 4 + 2 = 0 = 2 2 2 Copf = 4/3 NF Now CARE and Cope are in parallel. Then the capacitance is (k = CABE + CeoF = 3 + 2 = 17 NF Ck CG a Now Ck and CG are in series Therefose the effective capacitance, 15, Cos = Y ex + VCG = 2 + 1 - 2 = 35 NF req = 6 = 1.457 pf = equivalent capacitance betweer point a and 6.