Just question2(a) please. Thanks
Just question2(a) please. Thanks 2. An 10 kg object is hung from a spring attached to...
In a hurry to digest this . Tks for the help (thumb up) 2. A mass of m kilograms (kg) is mounted on top of a vertical spring. The spring is L metres long when disengaged and the end not attached to the mass is fixed to the ground. The mass moves vertically up and down, acted on by gravity, the restoring force T of the spring and the damping force R due to friction: see the diagram below The...
A 2kg mass is suspended vertically from a spring attached to a fixed support. The spring satisfies Hooke's law with a spring constant of k 18 N m1. No damping is present. Gravity acts on the mass with a gravitational constant of g 10 m s2. An external force of R 24 sin (wt) Newton is applied to the mass, directed downwards, where t is the time in seconds since the mass was set in motion and w is a...
A mass of m kilograams (kg) is mounted on top of a vertical spring. The spring is L metres long when disengaged and the end not attached to the mass is fixced to the ground. The mass moves vertically up and down, acted on by gravity, the restoring force T of the spring and the damping force R due to friction: see the diagram below The gravitational force is mg dowswards, where g- 9.8m is acceleration due to gravity, measured...
A spring is suspended vertically from a fixed support. The spring has spring constant k=24 N m −1 k=24 N m−1 . An object of mass m= 1 4 kg m=14 kg is attached to the bottom of the spring. The subject is subject to damping with damping constant β N m −1 s β N m−1 s . Let y(t) y(t) be the displacement in metres at the end of the spring below its equilibrium position, at time t...
21. A mass weighing 122.5 g stretches a spring by 7- F(f)-0.2e-2 N. The spring is set in motion from its equilibrium position with a downward velocity of I m/s. Find an equation for the position of the spring at any time t. A cm. The damping constant is c 0.4. External vibrations create a force of 32 21. A mass weighing 122.5 g stretches a spring by 7- F(f)-0.2e-2 N. The spring is set in motion from its equilibrium...
A spring is suspended vertically from a fixed support. The spring has spring constant k=24 N m −1 k=24 N m−1 . An object of mass m= 1 4 kg m=14 kg is attached to the bottom of the spring. The subject is subject to damping with damping constant β N m −1 s β N m−1 s . Let y(t) y(t) be the displacement in metres at the end of the spring below its equilibrium position, at time t...
An object weighing 16 lb streches a spring 3 in. The object is attached to a viscous damper with a damping constant of 2 lb-s/ft. If the object is set in motion from its equilibrium position by pulling it downward an additional 1 inch, find the position of the object at any time t.
ONLY attempt to solve if you know what you are doing. A mass of 1 kg is attached to a spring whose constant is 5 N/m. Initially, the mass is released 1 m below the equilibrium position with a downward velocity of 5 m/s, and the subsequent motion takes place in a medium that offers a damping force that is numerically equal to 2 times the instantaneous velocit y. a) Find the equation of motion if the mass is driven...
A spring is suspended vertically from a fixed support. the spring has spring constant k = 8nm^-1 (5 points) A spring is suspended vertically from a fixed support. The spring has spring constant k 8N m-1. An object of mass m kg is attached to the bottom of the spring. The subject is subject to damping with damping constant β N m-1 s. Let y(t) be the displacement in metres at the end of the spring below its equilibrium position,...
5 points) A spring is suspended vertically from a fixed support. The spring has spring constant k=28 N m−1k=28 N m−1. An object of mass m=14 kgm=14 kg is attached to the bottom of the spring. The subject is subject to damping with damping constant β N m−1 sβ N m−1 s. Let y(t)y(t) be the displacement in metres at the end of the spring below its equilibrium position, at time tt seconds. (5 poins) A spring is suspended vertically...