Question

FR #3.(30 pts): For the given line of current determine the force per unit length it would feel if a second line of current (1 = 4.56 Amperes) ran in the same direction at a distance of 0.833 m. 1 = 3.00 A If we consider the motion of a +3.33C charge (m = 2.54"?kg) being directed at the wire in the diagram below, derive the expression describing its closest approach: Xo Rs sin (8 4 then calculate its closest approach given the parameters specified in the diagram. (Hint: For the derivation, you will need to make use of RHR, AU = - - 7.di, and K = % mv2) 1 = 3,00 A 0 - 35 I v 400,000 m/s X = 3.5 m

Answer 1

The wires will experience a magnetic force that can be calculated as below

Given I, = 3:00 amp I 2=4.56 Amp Y 0.833 m 0.833m force between two cument carrying wire given hy sperated by a distance ris Hla Mo I, I2 e 2tr f (47x1077.m|A )-3.00 A) (4:5642 l 2KX 0.8 33 m f £= 2X3.004:56 X 107 321845 x Lot Nim .I 01 833 ala 3.285 xl 6 Nim [ current in same direction force will be attractive] or fi e 3.2854N/m this is force per unit leath