For the circuit shown in the figure, V = 60 V, C = 40
When the voltage across the cap is twice the voltage across
the resistor it is
V = (2* 60/3)
V = 40 Volts
so
charge Q = CV
Q = 40 uF * 40
Q = 1600 uC option A it is ----------<<<<<<<<<<Answer
Find I, in the circuit shown. 40 12 V 412 + 120 1212 60
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