Question

Language: Python

Topic: Dictionaries

Function name: catch_flight
Parameters: dictionary, tuple containing two strings

Returns: dictionary

Description: You’ve been stuck in NYC for around 8 months all by yourself because you haven’t been able to find a good time to fly home. You’re willing to go to any city but want to see how many flights to each location fit your budget.
You’re given a dictionary that has city names (strings) as the keys and a list of prices (list) and a tuple containing the range of prices (strings) that you are looking for (inclusive). Create a dictionary that has each city name (string) as a key with a value of the number of flight prices (int) that fall within your price range.

>>> cities = {'Atlanta': ['$7.31', '$8.46', '$24.03', '$12.00', '$8.30'], 'Orlando': ['$6.36', '$9.43', '$15.04', '$19.00'], 'Phoenix': ['$1.01', '$3.18', '$4.30', '$18.01']}
>>> prices = ('$8.30', '$17.00')
>>> print(catch_flight(cities, prices))

{'Atlanta': 3, 'Orlando': 2, 'Phoenix': 0}

Answer 1

catch flight.py - D:/Coding/PYTHON/catch flight.py (3.6.2) File Edit Format Run Options Window Help def catch flight (cities,prices) #Convert range to float r(float (prices [0] l:]),float (prices #Initialize dictionary for ans ans for city in cities: )) if city not in ans: ans[cityl0 #Comp are prices and add to ans for price in cities[city]: p float (price[l:]) if p r[0] and pr[1]: ans[cityl+-l return ans

OUTPUT :

SS3 /Coding/PYTHON/catch '$8.46', RESTART: D: ['$7.31', flight.py ーーーーーーーーーーーーーーー >>> cities = { 'Atlanta': '$24.03', '$12.00', '$8.30'], 'Orlando': '$6.36',$9.43', $15.04', '19.00', 'Phoenix': ['S1.01', '3.18','$4.30', '18 01'1 >>>pri<xs - '$8.30' '$17.00') >>> print (catch flight (cities, prices)) 'Atlanta': 3, 'Orlando' 2, Phoenix': 0) 3> In: 906 Col

CODE :

def catch_flight(cities,prices):
    #Convert range to float
    r = (float(prices[0][1:]),float(prices[1][1:]))
    #Initialize dictionary for ans
    ans = {}
    for city in cities:
        if city not in ans:
            ans[city] = 0
        #Compare prices and add to ans
        for price in cities[city]:
            p = float(price[1:])
            if p>=r[0] and p<=r[1]:
                ans[city]+=1
    return ans