Question

Given two particles with Q = 4.30-uc charges as shown in the figure below and a particle with charge q = 1.26 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = c.) x= -0.800 m 0 x= 0.800 m (a) What is the net force exerted by the two 4.30-uc charges on the charge q? (b) What is the electric field at the origin due to the two 4.30-uc particles? N/C (c) What is the electrical potential at the origin due to the two 4.30-uc particles? kV

Answer 1

Solution Charge Q = 4 300C - 4.30 x 1066 a = 1.26x1010 Aco.dou -20.doc a charges at A & B Force exerted by both given by FA and FB on charge at o is F = FA= Qa But the amplitude of Both FA and to equal and opposite in direction hence net Force Fret = F + F = 0 6] Similar to force electric field at origin due to charge at A&B is equal and opposite in direction EA = EB= I a 416 0.800) Enet - Eat E = 0 Em = EA + Eo =0 A E O EP - quantity and VA and Ve is some Electric potential is scalan VA = VB = I Q 491€ (opood = 9X100 4 4.30x106 0.800

V = V8 - 48.375X103 volt Net potential at origin Vnet = VA + Vo = (48.375 + 48.315) x 103 Vnet = 96.75x103 Vanet = 96.75 x103 volt.