Homework Answers
Weight oc Pbcl2 given = 0.0497 g
Molecular weight = 278.1 g/ mole.
No of moles of PbCl2 = weight of PbCl2 / molecular weight of PbCl2
Moles of PbCl2 = 0.0497 / 278.1
No lf moles of PbCl2 = 0.00017 moles in 1 litre.
So,
Concentration of PbCl2 = 0.00017 M.
concentration of [Cl^-] = 0.0165 M
Concentration of [Pb^2+] = 0.0392 M
Now,
Kc = [Pb^2+] * [Cl^-]^2 / [PbCl2]
Kc = 0.0392 * [0.0165]^2 / 0.00017
Kc = 0.06277
Kc = 6.27 * 10^-2
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