1) A 141 g sample of carbon from ancient wood is found to have an activity of 5.289 decays/min. a. How many half lives have elapsed since the tree was cut down? b. How many years have elapsed since the tree was cut down?
would appreciate any help
apply activity = dN/dt = LN
L = 5.289/60/141
L = 6.251*10^-4
as decay consatnt L = Ln2/T1/2
T/12 = 0.693/6.251 e-4
T/12 = 1108.48 years--------------answer to part B
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apply N = N0 e^-Lt
e^-Lt = 1/141) = 0.00709
-Lt = 4.94
t = 4.94/6.251 e-4 = 7916 .67 Years------answers A
decay constant (?): 5.289
half-life (t1/2): 0.13105448678389
mean lifetime (?): 0.18907165815844
1) A 141 g sample of carbon from ancient wood is found to have an activity...
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