Given grammer:
S → aSa | B
B → bB | E
Here E is ϵ
Answer:
Given grammer accepts all strings which contains even number of a's and any number of b's in middle position of a's string
For example:
aaaa
aabaa
aabbaa
aabbbaa
means number of a's is divisible by 2 and all b's are in center of a's.
b. Describe the language accepted by the following grammar: S→ Sa B B → B E
Theory of Computation
need ASAP 2-3 hours
1. For the following grammar: a) Give an example of a string accepted by the grammar. b) Give an example of a string not accepted by the grammar. c) Describe the language produced by the grammar. 2. Using the following grammar find a derivation for the string: 0001112 A0A1le C 0C2 | D Create a grammar for the language described by the following RE: Create a grammar for the following language: For the...
Consider the following grammar: <S> → <A> a <B> b <A> → <A> b | b <B> → a <B> | a Is the following sentence in the language generated by this grammar? baab Consider the following grammar: <S> → a <S> c <B> | <A> | b <A> → c <A> | c <B> → d | <A> Is the following sentence in the language generated by this grammar? acccbcc SHOW WORK
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Given that Σ={a,b}and using the appropriate notation,
describe the language that will be accepted by the FA
82 a a a b 04 q. b b 3 b
Consider the following grammar G: S'S SA xb AaAb B 3. do ed bisbon s LR Bx where S, A, and B are nonterminals, and a, b and x are terminals (a) [10] Is G SLR(1)? If yes, give the parsing table. Otherwise, explain why (b) [15] Is G LR(1)? If yes, give the parsing table. Otherwise, explain why. (c) [15] Is G LALR(1)? If yes, give the parsing table. Otherwise, explain why. umi
Consider the following grammar G: S'S...
Construct a regular grammar G (a" b) c (aa bb)? VT, S, P) that generates the language generated by
Construct a regular grammar G (a" b) c (aa bb)? VT, S, P) that generates the language generated by
For the following grammar (7 points) 1. B - Ba|A S - ABb A - Aba |A to find a grammar without A productions that generates the same language, we first identify non-terminals that drive A. These non-terminals are: A and B. Then from S - ABb, we construct S from A - Aba, we construct A - from B - Ba, we construct B - So, the grammar without A that generates the same language is: