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(16.0x10 8. (16 points) A charge Q: -5.0x10C) is placed on the x axis at x = 5.0 m, and a charge is placed on the x axis at x
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Answer #1

a)

F kq191 2 9*10* 5 * 10-6*6* 10-6 -= 2.23* 10-30 = =

b)

As Q1 is negatively charged and Q2 is positively charged Q2 attracts Q1 towards it. Therefore the direction of force is towards positive x-direction.

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