Question

My Notes Ask Your Teache 2. -13 points SerPSE10 8.2.P.003. and slides on the frictionless track shown in the figure A block of mass m 6.70 kg is released from rest from point below. (Leth, = 7.40 m.) S. 20 m 2.00 m (a) Determine the block's speed at points and ©. m/s (b) Determine the network done by the gravitational force on the block as it moves from point to point 0. Need Help? Read Watch It 3. -12 points SerPSE10 8.3.OP.006. My Notes Ask Your Teacher A sled is given a push across a horizontal surface. The sled has a mass m, the push gives it an initial speed of 1.90 m/s, and the coefficient of kinetic friction between the sled and the surface is 0.150. (a) Use energy considerations to find the distance (inm) the sled moves before it stops. (1) What If? Determine the stopping distance in m) for the sled if its initial speed is doubled to 3.80 m/s.

Answer 1

m = 6.70 kg = omis, ha = 7.40m his = 3.20m , hc = 2.00m (a) Applying conservahew of mechanical energy mgha ++ / m = mghe + 1 / mv → 6-70x9.81* 7.40 +5x6-70x02 = 6.70x 9.8183.20 + 1 X 6.70 x VB => *6.70 V - 6.70x9.81*7.40 -6.70x9.8183. 20 - 12 = 2x6.70x9.81(7-40-3.20) 6.7.0 =) Vo = √2x9.81*4:20 = 9:08 mis [VB = 9:08 m/s ngla + m = mghe + 2 mu =) 6.70x9.81*7.40 + 1x6.40 x02 = 6-70x9.81 + 2 + ₂ x 6.70x12 =) *X6-70 x V = 6.70x9.81*(7.40-2) =) 12 = 2x9.81 X8.40 =) Vc =12x9.81X5.40 = 10.3 mis TV = 10.3mis

Work done by the gravitational force on the block as it moves from point A to point hac = ing (ha-be) = 6.70x9.81 (7.40-2.00) = 6.7089.81 x 5.40 = 3555