Ans)
this is counting using ascii encoding from 'a'-'z' i.e 26 charctors are their
assuming alphabet[0] is counting for 'a' likewise others a[25] counting for 'z'
in below function we are reducing current char i.e str[i] - 'a' it will give the
difference between 'a' and given char which is equal to char in array
for example :
assume current chars is c then, 'c'-'a' =2 in ascii and in alphabet[2] will be incremented
alphabet[0] counting for a alphabet[1] for b and alphabet[2] for c
this is way its working
Code:
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int count[26]; // to store frequency of every alphabet
char* toCharArray(string out){ //to convert output string to char array
char* array;
array = new char[out.size() + 1];
for (int i = 0; i < out.size(); i++)
{
array[i] = out[i];
}
return array;
}
int main() { // main function
string filename,outfile;
cout << "Enter File name:";
cin >> filename;
cout << "Enter Full name and path of outfile:";
cin >> outfile;
ifstream file;
file.open((filename.c_str())); //if file does not exist
if (!file)
{
cout << "Cannot Open file";
return 0;
}
string out,temp;
out = "";
while (!file.eof()) //reading all charctors from file
{
getline(file,temp);
out.append(temp);
}
file.close();
char *str = toCharArray(out);
//please read this for better understanding
/*
this is counting using ascii encoding from a-z 26 charctors are their
assuming alphabet[0] is counting for 'a' likewise others a[25] counting for 'z'
in below function we are reducing current char i.e str[i] - 'a' it will give the
difference between 'a' and given char which is equal to char in array
for example :
assume current chars is c then, 'c'-'a' =2 in ascii and in alphabet[2] will be incremented
alphabet[0] counting for a alphabet[1] for b and alphabet[2] for c
this is way its working
*/
int i = 0, alphabet[26] = {0}, j;
while (str[i] != '\0') { //counting frequency of every alphabet
if (str[i] >= 'a' && str[i] <= 'z') {
j = str[i] - 'a';
++alphabet[j];
}
++i;
}
ofstream output;
output.open(outfile.c_str()); //opening output file
for (i = 0; i < 26; i++)
{
if (alphabet[i] == 0) //we are skipping char whose count is zero
{ //we will not put them into file
continue;
}
output << char(i + 'a') << " " << alphabet[i] << "\n";
}
return 0;
}
hi, please help in c++. I dont understand how to do this, and a lot of...
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