Question

A normal distribution has a mean of u = 80 with o = 20. What score separates the highest 15% of the distribution from the rest of the scores? (Hint: First find the Z-score, then convert back to a raw score.) OX= 59.2 X = 100.8 X =95 X = 65

Answer 1

Using standard normal table,

P(Z > z) = 15%

= 1 - P(Z < z) = 0.15

= P(Z < z ) = 1 - 0.15

= P(Z < z ) = 0.85

z =1.04 (using standard normal (Z) table )

Using z-score formula = raw score

x = z * $\sigma$ + $\mu$

x= 1.04 * 20+80

x= 100.8