Question

Fluid Dynamics

b. A gate of negligible weight is used to hold back water in a channel of width, b as shown in Figure Q2 (b). The force of the gate against the block is R. Determine R. Hinge h/2 Water Block RS Figure Q2 (b)

Answer 1

Solved the problem. For this analysis the gate
SOLUTION For this analysis, the gate was divided into two parts. The curred bop part and bottom vertical part. Force in horizondal direction (curved gate) xh Fx = PAG A = h b 2 h sh Fox, = 8. (1) (b) . g h 8 n2bg 4 8 force in vertical direction ( vertical gate) Fy=SAg xh. A = Trz 4 2 - II (h) ñ = b. Fy = f g h ²b 16
was divided into two parts.The curved top part and bottom vertical part.
force in horizondal direction (vertical gate) Fre - Sagh A = h b; n=th th 3 h. 4 너 . Fra sbg (M) (3 h) = 36g (3 h). R = J (Ex, t Fu2 )" + F 2 2 Y 2 2 18h² bg 2 + 34 bgh? +(3 bg 17 ) 8 2 2 :.R= / (1 sb gh? ) + ( + TS I/ Answer: 2 R = J G s bgn2e +11 +(1 TTS bgn²)