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Consider the following circuit. 200 ic a. Find i, if IA=0. o imat, fra, sa b. Find ig if IA =5A. um 10V $OM c. Find IA so tha
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Solo Given 202 lov ( as į if IA=0; 2012 VI lov .. Applying Kch aut node °c + IA = iB ...q=iB (: Ig=0) . Applying KUL to the lby is of IASA: 2050 Vo 55 Incs Tou 3 from node vo Nodal analysis : Assuming all curents are leaving → Applying ker at node :I e PA so that e=0; Applying KvL in first mesho KUL 0 + -10:+2012+5 cicIa) = 0 But i=0 -) -10 + 2(0) +500 + IH) - 0 I 5 Pa =

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