Question

The functions p(t) and g(t) are continuous for every t. It is stated that In(t+1) and sin(t) cannot both be solutions of the differential equation v +pg+qU 0. Which of the following imply this conclusion? A: The statement is incorrect. There exist a pair of everywhere continuous functions p(t) and g(t) that will make In(t+1) and sin(t) valid solutions B: The Wronskian of the two functions vanishes at but there are values oft where it does not vanish. C: If sin(t) were a solution, then the other solution would have to be cos(t). None b) Only (A) Only (B) Only ( (A) and (B) (A) and (C) (B) and (c)

Answer 1

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