Solution-1:
For mutually exclusive events
P(A and B)=0
But
P(AUB)=P)(A)+P(B)-P(A and B)
0.6=0.4+P(B)-0
P(B)=0.6-0.4
P(B)=0.2
For P(B)=0.2, A and B are mutually exclusive.
Solution-B:
If A and B are independent events
P(A and B)=P(A)*P(B)
P(AUB)=P)(A)+P(B)-P(A and B)
0.6=0.4+P(B)-0.4*P(B)
0.2=0.6P(B)
P(B)=0.2/0.6
P(B)=1/3
P(B)= 0.33333
so For P(B)=0.33333,A and B are independent
pts) 3. Let Pr(A) = 0.4 and Pr(AUB) = 0.6. (a) For what value of Pr(B)...
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