Calculate the Ni+2 concentration of a solution made by mixing 0.020 mole of solid Ni(NO3)2 into...

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Answer 1

Answer #1

number of moles of Ni(NO3)2=0.020

number of moles of NH4OH=0.22

NH4OH is in excess so the product obtained will be 0.020mole

[Ni(NH3)4]2+ ------> Ni2+ + 4NH3
0.02 - x x 4x

kd=x*4x/0.02 - x =1.1x10^-8(neglecting x in the denominator)

x=7.416x10^-6=concentration of Ni2+

Answer 2

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