Question

***Please give the java code for the below and add comments for different areas for a dummy to understand***

This java program will combine the techniques of handling arrays, decision control statements, and loops.

Your program should accomplish the following:

1. Build an array that holds characters (size 35)
2. Load the array with random capital letters (use random generator)
3. Your program should present a menu to the user allowing for the following “actions”.

1. To “search” for a target letter of the user’s choice.
   1. If found, the location (index) of the search target will be given (e.g. it is located in spot/index 8)
   2. If it is not found, a simple message saying it isn’t in the array is sufficient
2. A “count” to see how many times a letter (given to you by the user) is in the array
3. A “print” which will print out the contents of the array for the user

Notes for the above Java Program:

1. This program should consist of a handful of logical modules (procedures and functions). at least 3 methods in addition to “main”.
2. methods should really not be doing I/O – do all that and pass the information to the method(s) to be used. The methods should return the answer or appropriate information back to the calling statement for processing.
3. the menu should allow for multiple iterations (loop it) in addition to allowing the user to quit when desired.

Answer 1

SOURCE CODE IN JAVA:

import java.util.Scanner;
class character
{
//method to fill a character array with random capital alphabets
//we generate a number from 0 to 25 and add 65 to it, since we know ASCII of A-Z is 65-90
void fillArray(char a[])
{
for(int i=0;i<a.length;i++)
{
char c=(char)(65+(int)(Math.random()*26));
a[i]=c;
}
}
//method to find and return the index of first occurrence of a given character in given array
//returns -1 if not found
int findChar(char a[],char x)
{
for(int i=0;i<a.length;i++)
{
if(a[i]==x)
return i;
}
return -1;
}
//method to return number of times a given character occurs in a given array
int countChar(char a[],char x)
{
int count=0;
for(int i=0;i<a.length;i++)
{
if(a[i]==x)
count+=1;
}
return count;
}
//method to print the given array
void printArray(char a[])
{
for(int i=0;i<a.length;i++)
{
System.out.print(a[i]+" ");
}
System.out.println();
}
public static void main(String args[])
{
Scanner in=new Scanner(System.in); //Scanner object for inputs
character ob=new character(); //creating object of class
char a[]=new char[35]; //creating empty array
ob.fillArray(a); //filling the array
int ch;
char c;
do
{
System.out.println("1. Search, 2. Count, 3. Print and any other number to quit");
System.out.print("Enter your choice: ");
ch=in.nextInt(); //user choice input
switch(ch)
{
case 1:
System.out.print("Enter the character you want to search: "); //input prompt
c=in.next().charAt(0); //input
int search=ob.findChar(a,c);
if(search==-1)
System.out.println(c+" was not found");
else
System.out.println(c+" was found at position "+search);
break;
case 2:
System.out.print("Enter the character you want to count: "); //input prompt
c=in.next().charAt(0); //input
int count=ob.countChar(a,c);
System.out.println(c+" was found in the array "+count+" times");
break;
case 3:
ob.printArray(a);
break;
default:
System.out.println("Thank you for using this system!"); //if user chose to quit
}
System.out.println();
}while(ch>=1 && ch<=3);
}
}

OUTPUT:

Blue): Terminal Window - Rik Options 1. Search, 2. Count, 3. Print and any other number to quit Enter your choice: 3 IIRCE JOOV XRIKGU XUGH VCGCENIRWQBWIMYR 1. Search, 2. Count, 3. Print and any other number to quit Enter your choice: 1 Enter the character you want to search: G Gwas found at position 13 1. Search, 2. Count, 3. Print and any other number to quit Enter your choice: 2 Enter the character you want to count: A A was found in the array o times 1. Search, 2. Count, 3. Print and any other number to quit Enter your choice: 2 Enter the character you want to count: 0 O was found in the array 2 times 1. Search, 2. Count, 3. Print and any other number to quit Enter your choice: 4 Thank you for using this system!