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The current through a 50 ohm resistor is I = (0.80 A) sin(240t). What are (a)...

The current through a 50 ohm resistor is I = (0.80 A) sin(240t). What are (a) the current amplitude (maximum current) and (b) the rms current? (c) Id the resistor is replaced by a 10-micro F capacitor, what will be the capacitive resistance of the circuit?

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Answer #1

R = 50 ohm I = 0.80 Sim 1240+) a) maximum current = 0.80A Max Current - =0.506A 0.566 A b> Roms current = Mancurrent = c> c=

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