Calculate the molar solubility of Fe(OH)3 if its Ksp equals 4.0 × 10 38.
A) 2.0 × 10 10 M B) 2.6 × 10 10 M C) 4.5 × 10 10 M D) 1.2 × 10 19 M E) 2.0 × 10 19 M
Ksp of Fe(OH)3 = s x (3s)3 = 27 s4
Given Ksp of Fe(OH)3 = 4.0 × 1038
So, 27 s4 = 4.0 × 1038
s4 = 14.81 x 1036
s = (14.81 x 1036)1/4
S = 1.96 x 109 M
Solubility = 2 x 109 M approx
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