Question

Question 15 You have an unknown concentration of reactant A to form products B in a closed system (see the following equilibrium). Initially there is no product B at the beginning of the reaction. A (aq) — B(aq) K = 1.0 If the equilibrium constant is doubled (K = 2.0), how will the percentage yield of product B change at equilibrium state? The yield will increase by 33%. More information is needed for this question The yield will increase a double The yield will increase by 50%. Next

Answer 1

The first option is correct among the four options, i.e The yield will increase by 33%.

Solution A (aq) A(ap) =01ap) (04) [K=sv] (Ailialty) ( l It u consider initially Lo Home Hentl mel alam t-tq 1.0-8 a keq - 10 = [roduddo al equilibrium Reactors) (7 yield of - (50%) Sas 0.5 x 100} 1-X OY product 1.0 20=1 2015 moles) Alaq) = Blag? . (secondly) K = 2.0 at to 1.0 mole at t= teg 1.0-9 a kq = 2.0 = [Bat equilibrium % yield = x 100 = 2.0-2 by Product B 1.0 3x > 2.0 66.66% 4x = 8% moles) on doubling the equilibrium => = 16.667. x100 50%. * Now % change in yield of product B constant ko 166-66-50)% x 100 % change = 50% = 33.3% / Any Henu option @[1st option is correct Increase by 33% se The yield will 1.