Answer:
Let introductory fixation [HA]0= xM
The harmony fixation [HA]= (100-8.01)/100xM
=0.9199xM
The adjustment in fixation [HA]0-[HA]= 0.0801x M =[A^-]=[H^+]
The balance consistent K_a = [H^+][A^-] / [HA]= (0.0801x *0.0801x) /0.9199x = .00697x
Henceforth, the underlying centralization of a feeble corrosive is x/Ka =x/0.00697x =143.5
Henceforth, numerous of Ka should the underlying convergence of a powerless corrosive surpass, for the underlying fixation and the balance focus to be inside 8.01 percent of one another will be =143.5-1 =142.5
various of Ka
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