Question

Q3: The switch in the has been open a long time before closing at t=0. Find il(t) for t> 0. 2k12 t = 0 =0%. iL 12V 6 k92 62.5H 2.5 UF 9 mA

Answer 1

30 0 ta w oru La 13 625M @ 120 amp Q.SMF The switch was open for tco The circuit is in steady date. In stady state capacitor ads as open circuit and inductor acts as short cirant. The circuit becomes, (((0) = -12 lok akh w Yico) 12V L (0) ²-6mA Grauit ay akr for too the switch was closed. The Crait is in steady state. Insteady indudor acts short Grauit. The circuit become state capacitor acts cy open Across 6 kr there is short circuit path So gun resistance is removed because Qama there is no curtment How. The circuit becomes, Applying kul to the circuits m forn riccos 12V Quel um 12 + OKI -0. Amal Ficco) G Qizv I=-6mA :ico): 9m-6m 1260): 3mA. Rea : 64/12k : 6K2K 6k+2K 12 SK SL

Y. 62.5 T.Sk. 2: 0.0416784 i_01 (+(1.09.-1.cop] e ] mp 3m +[-om-3m] : oui 4(b) = (3-9. 9.884+] m A