Question

Q1: Find Vc(t) fort> 0 using general solution. + 10V 20V 0.15F 5Ω

Answer 1

to ov + lov Yello) sur 0.157 toy We under txo switch is at position ② and at inis posption erruit is in steady state state capacitor behaves Open cirenit ( X = 0 ) at t=0 o ccross Capacitor = Velo-) stedely 04 Let vo volty 10v +0 20v Velo) j 502 apply love in the loop -20 + 2 i + 10 51 5.5 Fe 20-0 10 J = 7

Non Velo) 20i ei 32-0 2X10 7 -20 7 Vafo =171428 V all of S Cabautor Cannot change instantly ve lon) = vel0+) Evelo) : 17.14281 ie of t=o switch is moved to position ② 22 lov + 502 0-105 Under Again stessly staicte Capcstor be hares as open circuit. Let at ta Voltage a ceross Cupanitor ve (oo) an TH • 502 Filmas po ferro

aupply Kut in the loop 10t sila) + (a) = 0 10 film) - (a) Voltage a cenoss Capacitor. Velm) - (2n) 1.foo) =? : 2 x 10 v Ven) = 2.85710 time constant of conuit T Rey C Req= resistance neen terminal keeping sourle by cupenitor deactive 1 5 pea 582 Req 5211 zn 5+2

to 0.15 fo 7 1.5 T see 7 t/e Vill) Velo) t eneration solution of Caparitor rootege + (veros --Velas) 2.8571 + (17.1426 - 2.8571) =- 2.8591 + 14.2856 e 45+ 4.667 t Velt) = e 1.5 V 2.857 + 14.285 e *** t>o voltage allness Coapuitos to