Question 5 of 14 After an afternoon party, a small cooler full of ice is dumped...

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Answer 1

Answer #1

Solution-

From the question we havemass of the ice= 4.50 kg= 4.50*10^3 g

The heat of fusion= 80 cal/g

So the required heat to met all the ice at zero degree C

= mass* heat of fusion

= (4.50*10^3)*(80)

=3.6e5 cal

Answer 2

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