Question

2. In a physics experiment, a 60.0 h resistor is used to discharge fully charged 90.0 mf capacitor. Determina the time when there is on the capacitor. 20% of initial energy remaining

Please, using formula

Answer 1

C = 90.0uF - Potential at any timet Present on capacitor V = Voetke MW R=6o.on Energy store in capoutor at any time t Ult) = Icuz = 1c (voete) 2 -$t Iclo2 e Re where 1 cuo²=uo = Instof -2t U(t) = Uo e RC energy given t= ? at which UEH) = 204. of to - 2t - 20 Uo 0.24% = Mo - 2 - 2t -0.2 No 0.2= e Re RC talking Hatural log both side ln (0.2) = - 2tlne RC In 10.2) = -2t RC - 1.61 = 26 -1.61= n2t RC RC Next Page

1.61 = zt RC t = 1.61RC C. see t = 1.61 X 6010 890.0x10 2 f t=8640x10 see 2 t=4320x10b see t = 4.32x103 Soe It = 4.32ms