Question

iii E.LT Аавьсаl Аавьс | АаВЬСcl| Аавьсс . Аавьссс Аав АаВЬС Аавьс Emphasis Heading 1 Strong Subtitle 1 No Spac... Subtle E- T Normal Title Paragraph Styles Examine the frequency characteristic of an audio frequency oscillator by varying the component's values, as shown in Fig. The following data is available. B=1/3, R1=40-49K2, R2-45-5222, C1=0.001-0.003F C2=0.002-0.005uF. Figure out the resonance frequency as well based on data variability Explain why this kind of oscillator only operates at resonance frequency. Aid with circuit explanation R4 vo RI 다 HE ER

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Answer 1

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Given that, ß= 1/3 - R-40-49ks, R = 45-5-kr, c, = 0.001-0.003 MF, C₂=0.002-0.005 MF " we can see that the crait given is a weinbridge oscillator. Barh ausen site sia should be followed for getting Sustained ascillations. Then, IABI=1. Then AX 1 2 1 = 1 A=3 Rf - Phaseshitt must be alor) 360. And = 3. R; Then, Rf=2; Ri= loka Resonant frequency is given by, fo= 1+ Rf=roke 271 R, Raila maximum as R = 40k, c,=0.000uF, R2=45kg, ca = 0.002.ut. By substituting, we get to) 2.65kHz Minimum R = 4 ako, Ruasokn, c, = 0.00uF, (₂=0.0084 of By Golvly weget, (to min 814.50 Hz