Question

PLEASE ANSWER ALL PROBLEMS CORRECTLY.

THANK YOU FOR YOUR HELP!

PROBLEM 1

11:59:00 PM (10%) Problem 2: A student constructs a simple constant volume gas thermometer and calibrates it using the boiling point of water, 100°C, and the freezing point of a specific brine solution, -19°C. The pressures measured at the calibration points are 1.366 atm and 0.9267 atm, respectively. From these data, what temperature will the student calculate, in degrees Celsius, for the value of absolute zero? T= Grade SL Deductio: Potential

PROBLEM 2

PROBLEM 3

Answer 1

Problem & For constant volume gas thermometen, P&T P-ATTO A= slope = P2-P, T2-T 1-366-0.9267 100-(-19) A=0.00369 afm/ec P=0.00369T+B when T= -19°c P= . 0.9267 atm 0.9267=0.00369 (-19) + B B = 0.9267 +0.070|| B=0.9468 P=0.00369 T +0.9968 At absolute zero, P=0 0.00369 T +0.9968 T= -0.9968 0.00369 T=-270. 14°C

Problem 2 L = 3om B =2om Let L and Bi are the length and breeath at temperature 22.5°c L=L(1+&AT) 21 = 30(1+1-2x10-5(22.5-20)) L = 30.0oog on B = B(1+28T) Bj = 2011+1-2805*(22-5-20)) B = 20.0oobm A = LB = 30820 = boom? A, = L, B, = 30.00098 20.0006 = 600.036 m² change in area , AA = A, -A = 600.036-600 - 0.036 m² change in total price $60,000x 0.036 = $2160 chang in total price in $ 2160