Question

(Dynamics Examination) ist 1, S: 4 If a partide moves along a curve with a constant speed, then its tangential component of acceleration is A: zero. B: positive. C. constant D: negative. 2. 单选题的重点 The position, s. is given as a function of angular positione. as s = 10 sin(28). The velocity, v, is A: 20 sin(2) B: 20 cos(20) C: 20 w cos(20) D: 20 w sin(2) 3. S10 The 15-kg disk is pinned at and is initially at rest. If a 10-9 bullet is fired into the disk with a velocity of 200 m/s. aximum angle 8 to which the disk swings.The bullet becomes embedded in the disk Taper ici pour rechercher O RE

Answer 1

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1)

Option-A.   

If a particle moves along curve with constant speed its tangential conponent of accleration is ZERO

2)OPTION-B

Given S=10 Sin( 2$\Theta$​​​​​​)

i, e...... S = 10 Sin2(wt)

Velocity(V) =dS/dt= 20w Cos(wt) =20w Cos ($\Theta$​​​​​​)

Velocity ( V) =20wcos(2$\Theta$)

3) Option - A

momentus Conservation of angular ý (Ho), (Holz 0.15 B X15X60-15/+1560-157]w = = = 0.01 (200605 38) C0.15) 1519.812N W-005132 rad/sec From Conservation of Energy TitY = TtY₂ [ +15 +15+ (0-155°+1560.15)) (0-5132)+70 = 041569-81(0.15) (1-coso) 2 o o=4.45

4)Option - d

VA on rigid boods or IC that has B A At point in its Extension Zero Velocity is Instataneous Centre called of Velocity VB In Case of AIB , we have Velocities parallel but opposite direction . So Ic lies at mid Point of line Connecting two points CS Scanned with CamScanner

  

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