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AS FAL: 1.0x1/5 + 1.0x1/5 + 1.0x1/5 + 1.0x1/5 + 1.0x1/5 = 20% + 20% + 20% + 20% + 20% 6 Original Response Unfiltered Response
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Answer #1

Given Т. Јz + and T is maximum. 4he Surface 818, 2) = 3х4 40°+22 4 го We have to find (2,4, 2 st solution points = ( 1 / 3 f2UX4 & we get on x2 -24 122+ + 2x2²_o I- = 2x(2² 12 e²) = 0 Casey from Fild, let ato Xto =) z? 12x²=0 = 2 E o = 2² 1282 then fPutting the values of no + 14/15 ,= 트 in the surface, we get 31 %) +41 + 2? 6=0 ) It i-6+ 2²0 =) 2= 4 2= 9 12:42 then solving

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AS FAL: 1.0x1/5 + 1.0x1/5 + 1.0x1/5 + 1.0x1/5 + 1.0x1/5 = 20% + 20% +...
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