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Any help on 27-30 would be greatly appreciated.
Use the given information to find the exact value of the expression. Draw and label the triangles. 9 0 27) csc = e in quadran
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277 given that, CSco= old Hind 111 : CSCO =-2 / ON, sino- As esco=1 .] Sino coso = 1-sinuo As o in quadrant III Coso will betano a 2 77 Since, 2 tano tan 20 = Ir tanto 2 2. 19 VFF 1-4 77. 4 77 73 77 4 - 77 x V7 73 ol 4/7 73 tan 20 4/7 - 73since, cos o == It coso 2 2 As o is in quadrant IIL , cose will be negative : coses 14 coso 2 1- 1- V7 (l 9 9-√7 9 9-7 = - 329) sin 3x = V3 2 OM Sin 34 Sin 5 ON 3x = I w/7 OM 9 sino is Positive in quadrant I and II TT In quadrant I; xa In quadrant I

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