Question

Write an equation of the form y= a sin bx or y = a cosbx to describe the graph below. 0/0 3 2 л sin cos 1- - 42 -22 25 42 67 81 10, 12: O=O -2- х 5 ?

Answer 1

The solution is given below

standard equatios we can see of graph is 2 2 2 -O We know that the of cosine function is s acos bla-c) t-d. And from the graph; that the Imaximum valu the is 4 and minimum value is -4. Now, amplitude a= max-min - 444 4-64) 4+4 Q a=4 2 And since one pole is completed from x to so period = BA And we that b = 20 K. 1 period 4 44 phan shift And vertical shift d = max-min 2 d 4-4 2 Thus, the equation equation of the given. y=46035 know c=0