Solve the equation in the interval [0°, 360°).
4 sin^2θ = 3
csc θ = 1 + cot θ
3 sin^2θ - sin θ - 4 = 0
2 cos^3θ = cos θ
1.
or,
2.
Dinomiator can't be Zero for real solution,
3.
4.
or,
Solve the equation in the interval [0°, 360°). 4 sin^2θ = 3 csc θ = 1...
Solve the equation in the interval [0°, 360°). sin^2θ - sin θ - 12 = 0 sin 2θ = -sin θ 2 cos2θ + 7 sin θ = 5
Solve the equation on the interval [0, 360°). (43 each) 1) 5 sin 0+1 = 3 sin 2) 2 cos2 + 3 cos 0 + 1 = 0
Use trigonometric identities to solve the equation 2sin(2θ)-2cos(θ)=0 exactly for 0≤θ≤2π. A.) What is 2sin(2θ) in terms of sin(θ)and cos(θ)? B.) After making the substitution from part 1, what is the common factor for the left side of the expression 2sin(2θ)-2cos(θ)=0 ? C.) Choose the correctly factored expression from below. a.) b.) c.) d.) We were unable to transcribe this imageAsin(e) cos(O) = 2cos(e) We were unable to transcribe this imageWe were unable to transcribe this image
M Inbox-ccorson2@iv Not Approximate e nearest 0.1° all angles θ in the interval 0° 360 that satisfy the equation Enter your answers as a comma separated list (a) sin θ=-0.3420 (b) cos - 0.7560 (c)--tan θ-2.889 (d) cot θ -0.7801 (e) sec θ -1.312 (f) csc θ-1.287
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2. Solve the given trigonometric equation using Pythagorian Identities, cos? 0 + sin? 0 = 1, 1+tan? 0 = sec, cot? 0+1 = csc 0. (a) 1 - 2 sin’x = cos r. (b) 4 sin’t - 5 sin x - 2 cos” x = 2. (c) 2 tang - 2 sec1+1= = tan”.