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Question 2 (1 point) For the water in the pictures (its a little bit muddy) the index of refraction is 1.366. What is the an
O 60. water 30.9 37 degrees 19 degrees 23 degrees 48 degrees 43 degrees
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Answer #1

i=Angle of incidence= 30 degree

r=Angle of refraction

nw=refractive index of water= 1.66

na=refractive index of air= 1

Using snell's law,

nwsini= nasinr

1.366*sin(30)= 1*sinr

sinr= 1.366/2

r=sin-1(1.366/2)= 43.08 \approx 43 degree

Answer: Option E

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