Question

Problem 8.24 29 of 36 n Review | Constants A 6.00 g bullet is fired horizontally into a 1.40 kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.200. The bullet remains embedded in the block, which is observed to slide 0.200 m along the surface before stopping. Part A What was the initial speed of the bullet? AEO ? v = 222.617 m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining

Answer 1

Bellet mass (m ) = 69 0.006 lag Block meuss (no) 1:40bg a ce mis Bullet velocity Block relocity = o mis Bullet and Blocke velocity = V mls Lebficient of kinetic friction = the 2020. Distance travelled after collision d = 0.2om final velocity after collision (of 20 mls conserve Energy after collision. kinetic energy Energy dissipated friction by ₂ (m + m) v² = Me (mm) gd 2 2 Mk go gd v=52 Magd 2 x 0,20x9USI X Os 20 V=0.885 mls.

linear momentum conserve muitra (0) (mum) v (MAM) v Co.0064140) XO-395 les mi 0.006 207.59.3 mls e - 20%. 6 mis