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A string is wound around a disk of mass M = 215 kg and a radius...

A string is wound around a disk of mass M = 215 kg and a radius of R = 0.310 m. The disk is free to rotate about its center by a frictionless pin. The other end of the string is attached to a mass m = 87.0 kg. The mass is released from rest and travels downward causing the cylinder to rotate. How many revolutions did the disk make 6 seconds after the release of mass m from rest?

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Answer #1

M,R . for the pulley T Thet =I.2 » T.R= ₂ MR? 2 → MRK T- 2 mg For the mass m, Fret =ma mg-T T = ma Also, the rope does not sl

2 Now, using o=Witt Žxt »o=0+ £x14.14x6² o = 254.53 radians. 254.53 2 Zł Number of revolutions N= Hence N=40.509 revolutions

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