Use a half-angle identity to find the exact value of the following expression. tan 112.5° Which...
Use a half-angle identity to find the exact value of the following expression. tan 15° Which of the following is the correct value of tan 15°? O A. -2-13 OB. -2+ V3 O C. 2+ 3 OD. 2-13
This Question: 1 pt Use a double-angle identity to find the exact value of the expression 2 tan 105° 1 - tan 105° Choose the correct answer below. OA-1 ОВ. va O C. 1 OD. OD ck to select your answer. Previous 2 tan 105 1 - tan2105 D B. 3 3 C. 1 OD. 2 OF. V2 3 V3 3 E. k to select your answer. Previous
QUESTION 12 Use a double-angle or half-angle identity to find the exact value of: cos(0) = and 270° <=< 360°, find sin 5 OAV10 10 B. 10 C. None of these OD 10 3 17 OE 4 QUESTION 13 Use a double-angle or half-angle identity to find the exact value of: 3 sin(0)= and 0° <o<90° , find tan 5 - šar 10 OA. 3 B.V10 Octs OD. -V10 E V30 QUESTION 11 Use a double-angle or half-angle identity to...
Use a double-angle identity to find the exact value of the expression 2 cos 15º - 1 OB. - 3 OA. 2 13 OC. 13 OD 2 V3 1 OF. OE 2 w Click to select your answer. Previous
Find the exact value of cos 75° using the half-angle identity. Choose the exact value of cos 75° ОА. 12-15 V3 B Ос. √2-√3 ID. √2+√3 2 4 2 2
Use an identity to simplify the following expression. tan 9° 1 - tan?9° Choose the correct expression equal to tan 9° below. 1-tan 290 O A. sin 18° OB. 1 cos 90 O C. 1 tan 18° OD. 1 3 tan z tan gº
Use a double-angle identity to find the exact value of the expression. 2 cos 267.5° - 1 - 2
x (x) 51 3. Use a half-angle formula to find the exact value of tan 12
Problem D Find the exact value of each expression. If the answer is an angle, the angle must be in radians. 1) sec tan-- V3 2) cos tan 2 5 I 8 4) tan sin 3) sintan 17 6) cos- 5) cos(sin
Find sin 105° first using a difference identity and then using a half-angle identity. Then compare the results. Which expression is a difference identity applied to sin 105°? Choose the correct answer. O A. sin 135º cos 30° + cos 135° sin 30° OB. sin 135° sin 30° - cos 135º cos 30° O c. sin 135° sin 30° + cos 135º cos 30° OD. sin 135ºcos 30° - cos 135º sin 30°