Question

In the RLC circuit shown, the inductor is a solenoid with 300 turns, 12 cm length & 5 mm diameter. Find the rms current throu

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Answer #1

-0.1062 X ca 6 ) af (sou) ( 30 cх 10-0 Impedance 2=5 R²+x2= 10.5² +0.1062 -o.SIIR 1.2v 2.35 A Iz >W - Or Slla

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