Question

I keep getting question incorrect. Not sure what I am doing wrong. Can someone please help.

Answer I got was -4.3225N

Use the data in the table below, which gives the position of a block connected to a horizontal spring at several times, for a block of mass m = 0.290 kg and assume friction is negligible. Time of measurement, t(s) Position of block, x (m) 0 4.75 0.25 3.36 0.50 0 0.75 -3.36 1.00 -4.75 1.25 1 -3.36 1.50 0 1.75 3.36 2.00 4.75 3.36 2.25 2.50 0 (a) Write an expression for the force FH exerted by the spring on the block. (Use the following as necessary: t. Assume Fy is measured in newtons. Do not include units in your answer.) FH = 4.3225 X (b) Sketch FH versus t. FH(N) FH(N) 101 5 t(s) 9.5 1.0 1.5 2.0 3.0 0.5 1.0 1.5 2.0 2.5 3.0 -51 -101 -10 FH (N) FH (N)

Answer 1

Given mass of block m= 0.29 kg From given data period of SHM T=&sec, and Amplitude of SHM A=4.75 m and at t=0 & CH = 4.75m so 2T Angular frequency wa {x3.14 radl sec = a'r w=3.14 rad/ sec. Force due tie spring is given by Frokx where negative sign gives direction of force so magnitude of force will be Fct) =-k act) but here alt= Acos (wt) & ka mw² in Exp =-MW? A cos (lot) = FACE) =-0.29+(3:14) 2x 4.75 Nx cos (3.14 rad xt sec Fr(t) = (- 13.58 Nx cos(3.14 rad xt sec